Uses of Interface
org.modelio.vcore.smkernel.mapi.MMetamodelFragment

Packages that use MMetamodelFragment

Package	Description
org.modelio.vcore.smkernel.mapi
org.modelio.vcore.smkernel.mapi.services

Uses of MMetamodelFragment in org.modelio.vcore.smkernel.mapi

Methods in org.modelio.vcore.smkernel.mapi that return MMetamodelFragment

Modifier and Type	Method and Description
MMetamodelFragment	MClass.getOrigin() Get the metamodel fragment providing this metaclass.

Methods in org.modelio.vcore.smkernel.mapi that return types with arguments of type MMetamodelFragment

Modifier and Type	Method and Description
java.util.Collection<? extends MMetamodelFragment>	MMetamodel.getFragments() Get the registered metamodel fragments.
java.util.Collection<VersionedItem<MMetamodelFragment>>	MMetamodelFragment.getNeededFragments()
java.util.List<? extends MMetamodelFragment>	MMetamodel.getSortedFragments() Get the registered fragments sorted by dependencies.

Uses of MMetamodelFragment in org.modelio.vcore.smkernel.mapi.services

Methods in org.modelio.vcore.smkernel.mapi.services with parameters of type MMetamodelFragment

Modifier and Type	Method and Description
S	MetamodelExtensionPoint.getService(MMetamodelFragment metamodelFragment) Get a service for the given metamodel fragment.
S	IMetamodelServiceProvider.getService(MMetamodelFragment metamodelFragment) Get the service for a metamodel fragment.

Method parameters in org.modelio.vcore.smkernel.mapi.services with type arguments of type MMetamodelFragment

Modifier and Type	Method and Description
void	MetamodelExtensionPoint.registerExtension(S service, java.lang.Class<? extends MMetamodelFragment> metamodelFragmentClass) Register a metamodel extension.
void	MetamodelExtensionPoint.unregisterExtension(java.lang.Class<? extends MMetamodelFragment> metamodelFragmentClass) Remove a metamodel service provider.